(3/(v-5))+(4/(v^2-25))=(1/(v+5))

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Solution for (3/(v-5))+(4/(v^2-25))=(1/(v+5)) equation: 


D( v )

v^2-25 = 0

v-5 = 0

v+5 = 0

v^2-25 = 0

v^2-25 = 0

1*v^2 = 25 // : 1

v^2 = 25

v^2 = 25 // ^ 1/2

abs(v) = 5

v = 5 or v = -5

v-5 = 0

v-5 = 0

v-5 = 0 // + 5

v = 5

v+5 = 0

v+5 = 0

v+5 = 0 // - 5

v = -5

v in (-oo:-5) U (-5:5) U (5:+oo)

3/(v-5)+4/(v^2-25) = 1/(v+5) // - 1/(v+5)

3/(v-5)+4/(v^2-25)-(1/(v+5)) = 0

3/(v-5)+4/(v^2-25)-(v+5)^-1 = 0

3/(v-5)+4/(v^2-25)-1/(v+5) = 0

(3*(v^2-25)*(v+5))/((v-5)*(v^2-25)*(v+5))+(4*(v-5)*(v+5))/((v-5)*(v^2-25)*(v+5))+(-1*(v-5)*(v^2-25))/((v-5)*(v^2-25)*(v+5)) = 0

3*(v^2-25)*(v+5)+4*(v-5)*(v+5)-1*(v-5)*(v^2-25) = 0

3*v^3-v^3+19*v^2+5*v^2-75*v+25*v-475-125 = 0

2*v^3+24*v^2-50*v-600 = 0

2*v^3+24*v^2-50*v-600 = 0

2*(v^3+12*v^2-25*v-300) = 0

v^3+12*v^2-25*v-300

v*(v^2-25)+12*v^2-300

12*(v^2-25)+v*(v^2-25)

(v+12)*(v^2-25)

2*(v+12)*(v^2-25) = 0

(2*(v+12)*(v^2-25))/((v-5)*(v^2-25)*(v+5)) = 0

(2*(v+12)*(v^2-25))/((v-5)*(v^2-25)*(v+5)) = 0 // * (v-5)*(v^2-25)*(v+5)

2*(v+12)*(v^2-25) = 0

( v+12 )

v+12 = 0 // - 12

v = -12

( v^2-25 )

1*v^2 = 25 // : 1

v^2 = 25

v^2 = 25 // ^ 1/2

abs(v) = 5

v = 5 or v = -5

v in { 5} 

v in { -5} 

v = -12

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